ᐅ Calculation of Electricity Consumption Based on Heating Demand?

Created on: 8 Feb 2018 20:02
T
tecker2010
Hi,

maybe someone can help me out here.
If I know the heat demand of my house, how can I estimate the approximate annual electricity consumption from that?

My heat demand is roughly 10 kW (including hot water). What other values do I need to calculate the electricity usage? I plan to generate the heat with a monovalent air-to-water heat pump.

I keep coming across full load hours (usually given as a standard 2,000 hours) and the annual performance factor (seasonal coefficient of performance) of a heat pump. Is that all I need?

10 kW * 2,000 h (hours) = 20,000 kWh (heat energy).
20,000 kWh / 2.8 (annual performance factor) = 7,143 kWh of electricity used. Is that correct? I know a detailed calculation is much more complex (transmission losses, etc.). A rough estimation would be enough, but I think I might be missing something and also find the 2,000 full load hours too approximate.

Looking forward to your feedback.
F
Fuchur
8 Feb 2018 21:42
Good, if you say so. I haven’t personally used any yet and have only read practical studies about them. Those showed results significantly below what is stated in the datasheet.
J
Joedreck
8 Feb 2018 22:34
Yes, that happens quite often because installation errors are obviously common. Unfortunately...
tecker20109 Feb 2018 09:15
Okay. The data was just an example. I was mainly interested in the calculation method. So, the 1,800 hours are used regardless of the type of heat pump generating the heat.
If the 1,800 hours are just a rough estimate, what data would be needed for a more precise calculation?
J
Joedreck
9 Feb 2018 10:06
So if you want to do it properly, you need a heating load calculation.

As a layperson, you can also use an online U-value calculator, provided the building components are known.

In my case, it matched quite well, I must say.
M
Malz1902
9 Feb 2018 10:52
We have an annual performance factor of 3.76. The heat pump is a Waterstage WSYP100DG6 / WPYA080LG with a heating capacity of 8 kW (8.8 kBtu/h). So in our case, would the calculation be 8 * 1800 / 3.76? Or should the nominal heating capacity of 7 kW (7.6 kBtu/h) be used for the calculation?
M
Malz1902
9 Feb 2018 11:17
The heat pump is a Watestage WSYA100DG6 / WOYA080LFCA

I made a mistake