Oh Yvonne,
I think our nonsense might have scared off the original poster.
Then I’ll provide some help for self-help. What’s needed is an image editing program. I like IrfanView including its plugin package, so everything here refers to that:
- Open the jpg file
- Press F12 to open the drawing dialog
- Click the ruler button
- Click and hold the left mouse button at the start point of a known distance (e.g., the 5m (16.4 ft) fire safety clearance)
- Drag the mouse to the endpoint and release
- A “Measure results” window appears showing the number of pixels (338.6 px)
- Close the results window with “OK” and repeat the process for the distance you want to measure (left orange line 172.0 px)
- Use a proportion calculation (rule of three): 5m (16.4 ft) / 338.6 = x / 172.0
- Solve for x: x = 172.0 / 338.6 * 5m (16.4 ft) = 2.54m (8.3 ft)
For a metrology expert, it’s certainly a piece of cake.
I think our nonsense might have scared off the original poster.
Then I’ll provide some help for self-help. What’s needed is an image editing program. I like IrfanView including its plugin package, so everything here refers to that:
- Open the jpg file
- Press F12 to open the drawing dialog
- Click the ruler button
- Click and hold the left mouse button at the start point of a known distance (e.g., the 5m (16.4 ft) fire safety clearance)
- Drag the mouse to the endpoint and release
- A “Measure results” window appears showing the number of pixels (338.6 px)
- Close the results window with “OK” and repeat the process for the distance you want to measure (left orange line 172.0 px)
- Use a proportion calculation (rule of three): 5m (16.4 ft) / 338.6 = x / 172.0
- Solve for x: x = 172.0 / 338.6 * 5m (16.4 ft) = 2.54m (8.3 ft)
For a metrology expert, it’s certainly a piece of cake.