Hello everyone,
As part of our house planning, we want to make all the preparations now to later install a photovoltaic system on our flat roof. We have already planned for an empty conduit to be laid from the flat roof to the utility room on the ground floor. Now, the construction company is asking what loads the roof should be designed for. We are currently contacting some suppliers.
Does anyone have experience or reference values regarding this? We definitely do not want the system to be rigidly attached to the roof or drilled in. It should be mounted on a frame, probably at an angle of about 25 to 30 degrees. Online, you often see figures of around 10 to 30 kg per square meter (2 to 6 pounds per square foot). Does that seem appropriate?
Thank you for your rough estimate.
As part of our house planning, we want to make all the preparations now to later install a photovoltaic system on our flat roof. We have already planned for an empty conduit to be laid from the flat roof to the utility room on the ground floor. Now, the construction company is asking what loads the roof should be designed for. We are currently contacting some suppliers.
Does anyone have experience or reference values regarding this? We definitely do not want the system to be rigidly attached to the roof or drilled in. It should be mounted on a frame, probably at an angle of about 25 to 30 degrees. Online, you often see figures of around 10 to 30 kg per square meter (2 to 6 pounds per square foot). Does that seem appropriate?
Thank you for your rough estimate.
I did some quick research online. Ads immediately show links to providers. Some offer an online configurator that calculates this for you. That should be sufficient as a rough estimate.
If that’s not enough for the construction company, you can tell them to design the roof for an extra load of x kg/m² (x pounds per square foot). Of course, don’t specify too generously, as that would cause unnecessary costs.
If that’s not enough for the construction company, you can tell them to design the roof for an extra load of x kg/m² (x pounds per square foot). Of course, don’t specify too generously, as that would cause unnecessary costs.